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On Monday 24 January 2005 6:06 pm, Neil Williams wrote:
How would the script be written to accept command line arguments to jump to that line?
Found it: #!/bin/bash usage="-j<int> jump to line number <int>" while getopts ":j:" options; do case $options in j ) jump=$OPTARG;; h ) echo $usage;; \? ) echo $usage exit 1;; * ) echo $usage exit 1;; esac done if [ $jump ] then echo Jumping to line $jump else echo jump not specified fi -- Neil Williams ============= http://www.dcglug.org.uk/ http://www.nosoftwarepatents.com/ http://sourceforge.net/projects/isbnsearch/ http://www.williamsleesmill.me.uk/ http://www.biglumber.com/x/web?qs=0x8801094A28BCB3E3
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