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On Monday 24 January 2005 6:06 pm, Neil Williams wrote:
How would the script be written to accept command line arguments to jump to that line?
Found it:
#!/bin/bash
usage="-j<int> jump to line number <int>"
while getopts ":j:" options; do
case $options in
j ) jump=$OPTARG;;
h ) echo $usage;;
\? ) echo $usage
exit 1;;
* ) echo $usage
exit 1;;
esac
done
if [ $jump ]
then
echo Jumping to line $jump
else
echo jump not specified
fi
--
Neil Williams
=============
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